-4n^2+204n=0

Solution for -4n^2+204n=0 equation:

-4n^2+204n=0

a = -4; b = 204; c = 0;
Δ = b2-4ac
Δ = 2042-4·(-4)·0
Δ = 41616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{41616}=204$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(204)-204}{2*-4}=\frac{-408}{-8}
=+51
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(204)+204}{2*-4}=\frac{0}{-8}
=0
$